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4x^2-118x-102=0
a = 4; b = -118; c = -102;
Δ = b2-4ac
Δ = -1182-4·4·(-102)
Δ = 15556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15556}=\sqrt{4*3889}=\sqrt{4}*\sqrt{3889}=2\sqrt{3889}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-118)-2\sqrt{3889}}{2*4}=\frac{118-2\sqrt{3889}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-118)+2\sqrt{3889}}{2*4}=\frac{118+2\sqrt{3889}}{8} $
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